A die is thrown, probability of following events: A number greater than or equal to 3 will app

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14.Probability

easy

A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.

$\frac{2}{3}$

Solution

The sample space of the given experiment is given by

$S=\{1,2,3,4,5,6\}$

Let $B$ be the event of the occurrence of a number greater than or equal to $3$ . Accordingly,

$B =\{3,4,5,6\}$

$\therefore P(B)=\frac{\text { Number of outcomes favourable to } B }{\text { Total number of possible outcomes }}=\frac{n(B)}{n(S)}=\frac{4}{6}=\frac{2}{3}$

Standard 11

Mathematics

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A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.

Solution

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${S_1}\,\,:\,\,A$ and $B \cup C$ are independent

${S_2}\,\,:\,\,A$ and $B \cap C$ are independent

Then