A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.
A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $B$ be the event of the occurrence of a number greater than or equal to $3$ . Accordingly,
$B =\{3,4,5,6\}$
$\therefore P(B)=\frac{\text { Number of outcomes favourable to } B }{\text { Total number of possible outcomes }}=\frac{n(B)}{n(S)}=\frac{4}{6}=\frac{2}{3}$
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- [KVPY 2014]
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